Angle Calculator (Right Triangle Solver)
This calculator solves for the missing angles and sides of any right-angled triangle. Enter the minimum two known values (two sides, or one side and one acute angle) in the corresponding fields below.
Enter Known Values (Minimum 2)
Angle $\gamma = 90^\circ$
Solved Triangle
Side Results
Angle Results
Step-by-Step Solution
The Core Formulas of Right Triangle Trigonometry
A right triangle is fully defined by three key relationships:
1. Pythagorean Theorem (Sides)
Used to find the length of any side when the other two sides are known:
Where $c$ is the hypotenuse (the side opposite the $90^\circ$ angle), and $a$ and $b$ are the legs.
2. Angle Sum Rule
The sum of the internal angles of any triangle is $180^\circ$ (or $\pi$ radians). Since the right angle $\gamma$ is $90^\circ$, the two acute angles ($\alpha$ and $\beta$) must sum to $90^\circ$:
3. SOHCAHTOA (Sides and Angles)
The trigonometric ratios relate the angles to the ratio of side lengths:
$$\sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}} \quad \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \quad \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}$$
To find a missing angle ($\theta$) when all sides are known, we use the inverse functions (arcsin, arccos, arctan): $\theta = \sin^{-1}(\frac{O}{H})$.
Frequently Asked Questions (FAQ)
What is SOHCAHTOA?
What is the sum of angles in a triangle?
What is the Law of Sines and Law of Cosines?
What is the required minimum input to solve a right triangle?
Formula (LaTeX) + variables + units
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a^2 + b^2 = c^2
\alpha + \beta + 90^\circ = 180^\circ \quad \text{or} \quad \alpha + \beta = 90^\circ
\sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}} \quad \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \quad \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}
c^2 = a^2 + b^2
\tan(\alpha) = \frac{a}{b}
$\alpha + \beta + 90^\circ = 180^\circ \quad \text{or} \quad \alpha + \beta = 90^\circ$
$\sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}} \quad \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \quad \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}$
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Last code update: 2026-01-19
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